Jawaban :
1. R infernya r = x^3 - 4
r + 4 = x^3
karena nilai r = x maka
x = r + 4 dibagi x^3
x = 1/1^3 r + 4/1
= r + 4
karena x = R
maka infers R = x^3 + 4 atau r + 4
2. f-1 = [tex] \frac{1}{x^2} + \frac{1}{x^2} = 11[/tex]
g-1 = [tex] \frac{1}{4} x - \frac{3}{4} = 25 [/tex]
b = 25 + 3/4 ; 1/4 = 412
r + 4 = x^3
karena nilai r = x maka
x = r + 4 dibagi x^3
x = 1/1^3 r + 4/1
= r + 4
karena x = R
maka infers R = x^3 + 4 atau r + 4
2. f-1 = [tex] \frac{1}{x^2} + \frac{1}{x^2} = 11[/tex]
g-1 = [tex] \frac{1}{4} x - \frac{3}{4} = 25 [/tex]
b = 25 + 3/4 ; 1/4 = 412
R(x) = x³ - 4
misal R(x) = y
y = x³ - 4
x³ = y + 4
x = [tex] \sqrt[3]{y + 4} [/tex]
[tex] R^{-1}(x) [/tex] = [tex] \sqrt[3]{x + 4} [/tex]
f(x) = x² - 1
y = x² - 1
x² = y + 1
x = [tex] \frac{+}{} [/tex][tex] \sqrt{y + 1} [/tex]
[tex] f^{-1}(x) [/tex] = [tex] \frac{+}{} [/tex][tex] \sqrt{x + 1} [/tex]
[tex] f^{-1}(a) [/tex] = 11
11 = [tex] \frac{+}{} [/tex][tex] \sqrt{a + 1} [/tex]
121 = a + 1
a = 120
lebihnya cari ndiri ya gan...:)
misal R(x) = y
y = x³ - 4
x³ = y + 4
x = [tex] \sqrt[3]{y + 4} [/tex]
[tex] R^{-1}(x) [/tex] = [tex] \sqrt[3]{x + 4} [/tex]
f(x) = x² - 1
y = x² - 1
x² = y + 1
x = [tex] \frac{+}{} [/tex][tex] \sqrt{y + 1} [/tex]
[tex] f^{-1}(x) [/tex] = [tex] \frac{+}{} [/tex][tex] \sqrt{x + 1} [/tex]
[tex] f^{-1}(a) [/tex] = 11
11 = [tex] \frac{+}{} [/tex][tex] \sqrt{a + 1} [/tex]
121 = a + 1
a = 120
lebihnya cari ndiri ya gan...:)