Jawaban :
misalkan ketiga bilangan tersebut
U1=(a-b)
U2=(a)
U3=(a+b)
(a-b)+(a)+(a+b) = 3
3a = 3 -> a= 1
(a-b) x (a) x (a+b) = -35
(1-b) (1) (1+b) = -35
(1-b²) = -35
b² = 36
b = +/- 6
* b= +6
u1 = 1-6 = -5 u2 = 1 u3= 1+6 = 7
*b= -6
u1 = 1-(-6) = 7 u2 = 1 u3= 1+(-6) = -5
jadi bilangannya -5 ; 1 ; dan 7
U1=(a-b)
U2=(a)
U3=(a+b)
(a-b)+(a)+(a+b) = 3
3a = 3 -> a= 1
(a-b) x (a) x (a+b) = -35
(1-b) (1) (1+b) = -35
(1-b²) = -35
b² = 36
b = +/- 6
* b= +6
u1 = 1-6 = -5 u2 = 1 u3= 1+6 = 7
*b= -6
u1 = 1-(-6) = 7 u2 = 1 u3= 1+(-6) = -5
jadi bilangannya -5 ; 1 ; dan 7