Jawaban :
a) rangkaian paralel ==> kp = 100 + 100 = 200 N/m
kp diseri dengan k3 = 200 ===> 1/ks = 1/200 + 1/200
1/ks = 2/200 ===> 1/ks = 1/100 ==> ks = 100 N/m
Jadi knstanta gaya total = 100 N/m
b) dik : Δx = 5 cm = 0,05 m ; k total = 100 N/m
F = k Δx
m . g = k . Δx ---> m . 10 = 100 . 0,05 ----> m = 0,5 kg
kp diseri dengan k3 = 200 ===> 1/ks = 1/200 + 1/200
1/ks = 2/200 ===> 1/ks = 1/100 ==> ks = 100 N/m
Jadi knstanta gaya total = 100 N/m
b) dik : Δx = 5 cm = 0,05 m ; k total = 100 N/m
F = k Δx
m . g = k . Δx ---> m . 10 = 100 . 0,05 ----> m = 0,5 kg
a) rangkaian paralel ==> kp = 100 + 100 = 200 N/m
kp diseri dengan k3 = 200 ===> 1/ks = 1/200 + 1/200
1/ks = 2/200 ===> 1/ks = 1/100 ==> ks = 100 N/m
Jadi knstanta gaya total = 100 N/m
b) dik : Δx = 5 cm = 0,05 m ; k total = 100 N/m
F = k Δx
m . g = k . Δx ---> m . 10 = 100 . 0,05 ----> m = 0,5 kg
kp diseri dengan k3 = 200 ===> 1/ks = 1/200 + 1/200
1/ks = 2/200 ===> 1/ks = 1/100 ==> ks = 100 N/m
Jadi knstanta gaya total = 100 N/m
b) dik : Δx = 5 cm = 0,05 m ; k total = 100 N/m
F = k Δx
m . g = k . Δx ---> m . 10 = 100 . 0,05 ----> m = 0,5 kg