Jawaban :
diketahui :
Lo = 50 cm
T2 = 30*C
α = 0.oooo12/*C
L = 50.0036 cm
ditanya
t1 = .....
jawab:
L = Lo(1 + α× ΔT)
= Lo( 1 + αT2 - αT1)
50.0036 = 50 (1 + 0.000012×30 - 0.000012×T1)
= 50 (1 + 0.00036 - 0.000012×T1)
= 50 ( 1.00036- 0.000012×T1)
= (50 ×1.00036) (50 × 0.000012×T1)
= 50.018 × 0.0006 × T1
= 0.03 × T1
T1 = 50.0036 / 0.03
≈ 16,67*C
tolong bantu ya koreksi kesalahannya :)
Lo = 50 cm
T2 = 30*C
α = 0.oooo12/*C
L = 50.0036 cm
ditanya
t1 = .....
jawab:
L = Lo(1 + α× ΔT)
= Lo( 1 + αT2 - αT1)
50.0036 = 50 (1 + 0.000012×30 - 0.000012×T1)
= 50 (1 + 0.00036 - 0.000012×T1)
= 50 ( 1.00036- 0.000012×T1)
= (50 ×1.00036) (50 × 0.000012×T1)
= 50.018 × 0.0006 × T1
= 0.03 × T1
T1 = 50.0036 / 0.03
≈ 16,67*C
tolong bantu ya koreksi kesalahannya :)